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  1. Two pipes can fill a tank with water in 15 and 12 hours respectively and a third pipe can empty it in 4 hours. If the pipes be opened in order at 8, 9 and 11 a.m. respectively, the tank will be emptied at
    1. 11 : 40 a.m.
    2. 12 : 40 p.m.
    3. 1 : 40 p.m.
    4. 2 : 40 p.m.
Correct Option: A

On the basis of given details in question ,

Part filled by A from 8 a.m to 11 a.m. =
3
=
1
155

Part filled by B from 9 a.m. to 11 a.m. =
2
=
1
126

Total Part filled till 11 a.m. =
1
+
1
=
6 + 5
=
11
563030

At 11 a.m. pipe C is opened to empty it.
∴ Part of tank emptied in 1 hour =
1
-
1
-
1
41512

Part of tank emptied in 1 hour =
15 - 4 - 5
=
1
6010

11
part will be emptied in
11
× 10 =
11
hours or 3
2
303033

i.e. 3 hours 40 minutes or at 11 : 40 a.m.
Therefore , the tank will be emptied at 11 : 40 a.m.



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