Pipes and Cistern
- Two pipes, P and Q, together can fill a cistern in 20 minutes and P alone can in 30 minutes. Then Q alone can fill the cistern in
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According to question ,
Part of the cistern filled by pipe Q in 1 minute = 1 - 1 = 3 - 2 = 1 20 30 60 60
Correct Option: B
According to question ,
Part of the cistern filled by pipe Q in 1 minute = 1 - 1 = 3 - 2 = 1 20 30 60 60
∴ Required time = 60 minutes
- Two pipes A and B can fill a cistern in 3 hours and 5 hours respectively. Pipe C can empty in 2 hours. If all the three pipes are open, in how many hours the cistern will be full?
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As per the given in question , we have
Part of cistern filled by two pipes in an hour = 1 + 1 3 5 Part of the tank emptied in 1 hour by pipe C = 1 2
Correct Option: D
As per the given in question , we have
Part of cistern filled by two pipes in an hour = 1 + 1 3 5 Part of the tank emptied in 1 hour by pipe C = 1 2 Part of cistern filled by three pipes in an hour = 1 + 1 - 1 = 10 + 6 - 15 = 1 3 5 2 30 30
Hence, the cistern will be filled in 30 hours.
- Three taps A, B, C can fill an overhead tank in 4, 6 and 12 hours respectively. How long would the three taps take to fill the tank if all of them are opened together ?
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On the basis of given details in question ,
Part of the tank filled by all three taps in an hour = 1 + 1 + 1 = 6 + 4 + 2 = 1 4 6 12 24 2
Correct Option: A
On the basis of given details in question ,
Part of the tank filled by all three taps in an hour = 1 + 1 + 1 = 6 + 4 + 2 = 1 4 6 12 24 2
∴ Hence, the tank will be filled in 2 hours.
- If two pipes function simultaneously, a tank is filled in 12 hours. One pipe fills the tank 10 hours faster than the other. How many hours does the faster pipe alone take to fill the tank?
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Let the slower pipe fills the tank in t hours, then
According to question ,∴ 1 + 1 = 1 t t - 10 12 ⇒ t - 10 + t = 1 t(t - 10) 12
⇒ t² – 10t = 24t – 120
⇒ t² – 34t + 120 = 0
⇒ t² – 30t – 4t + 120 = 0
Correct Option: A
Let the slower pipe fills the tank in t hours, then
According to question ,∴ 1 + 1 = 1 t t - 10 12 ⇒ t - 10 + t = 1 t(t - 10) 12
⇒ t² – 10t = 24t – 120
⇒ t² – 34t + 120 = 0
⇒ t² – 30t – 4t + 120 = 0
⇒ t (t – 30) – 4 (t – 30) = 0
⇒ (t – 4) (t – 30) = 0
∴ t = 30 because t ≠ 4
∴ Required time = 30 – 10 = 20 hours
- Two pipes X and Y can fill a cistern in 24 minutes and 32 minutes respectively. If both the pipes are opened together, then after how much time (in minutes) should Y be closed so that the tank is full in 18 minutes ?
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If pipe Y be closed after t minutes, then
According to question ,18 + t = 1 24 32 ⇒ t = 1 - 18 = 1 - 3 = 1 32 24 4 4 ⇒ t = 32 = 8 minutes 4
We can find required answer with the help of given formula :
Here , p = 24, q = 32, t = 18Required time = q 1 - t minutes p
Correct Option: B
If pipe Y be closed after t minutes, then
According to question ,18 + t = 1 24 32 ⇒ t = 1 - 18 = 1 - 3 = 1 32 24 4 4 ⇒ t = 32 = 8 minutes 4
We can find required answer with the help of given formula :
Here , p = 24, q = 32, t = 18Required time = q 1 - t minutes p Required time = 32 1 - 18 minutes 24 Required time = 32 1 - 3 4 Required time = 32 × 1 = 8 minutes 4