Pipes and Cistern


  1. Two pipes can fill a tank in 20 and 24 min, respectively and a waste pipe can empty 6 gallon per min. All the three pipes working together can fill the tank in 15 min. Find the capacity of the tank.









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    Part filled by 1st pipe in 1 min = 1/20
    Part filled by 2nd pipe in 1 min = 1/24
    Part filled by all the pipes in 1 min = 1/15
    Work done by the waste pipe 1 min
    = 1/15 - (1/20 + 1/24 )
    = 1/15 - 11/120
    = (8 - 11)/120 = ( - 3/120 ) = ( -1/40 )

    Correct Option: D

    Part filled by 1st pipe in 1 min = 1/20
    Part filled by 2nd pipe in 1 min = 1/24
    Part filled by all the pipes in 1 min = 1/15
    Work done by the waste pipe 1 min
    = 1/15 - (1/20 + 1/24 )
    = 1/15 - 11/120
    = (8 - 11)/120 = ( - 3/120 ) = ( -1/40 )
    [-ve sign indicates emptying]
    Now, volume of 1/40 part = 6 gallon
    ∴ Volume of whole tank = 40 x 6 = 240 gallon


  1. There are three pipes connected with a tank. The first pipe can fill 1/2 part of the tank in 1 h, second pipe can fill 1/3 part of the tank in 1 h. Third pipe is connected to empty the tank. After opening all the three pipes, 7/12 part of the tank can be filled in 1 h, then how long will third pipe take to empty the full tank.









  1. View Hint View Answer Discuss in Forum

    1st pipe takes 1 h to fill 1/2 part of the tank.
    So, time taken to fill the whole tank (m) = 2 h
    2nd pipe takes 1 h to 1/3 part of the tank
    So, time taken to fill the whole tank (n) = 3 h
    Let 3rd pipe takes P h to empty the tank = x
    ∴ 1/m + 1/n - 1/x = 7/12 ⇒ 1/2 + 1/3 - 1/x = 7/12
    ⇒ 1/x = (6 + 4 - 7)/12 = 3/12 = 1/4

    Correct Option: B

    1st pipe takes 1 h to fill 1/2 part of the tank.
    So, time taken to fill the whole tank (m) = 2 h
    2nd pipe takes 1 h to 1/3 part of the tank
    So, time taken to fill the whole tank (n) = 3 h
    Let 3rd pipe takes P h to empty the tank = x
    ∴ 1/m + 1/n - 1/x = 7/12 ⇒ 1/2 + 1/3 - 1/x = 7/12
    ⇒ 1/x = (6 + 4 - 7)/12 = 3/12 = 1/4
    ∴ x = 4 h



  1. Two pipes A and B are opened together to fill a tank. Both pipes fill the tank in a certain time. If A separately takes 16 min more than the time taken by ( A + B ) and B takes 9 min more than the time taken by ( A + B ). Find the time taken by A and B to fill the tank when both the pipes are opened together.









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    Here, a = 16 and = 9
    Required time = √ab

    Correct Option: B

    Here, a = 16 and = 9
    Required time = √ab
    16 x 9 = 4 x 3 = 12 min


  1. Two pipes P and Q can fill a cistern in 12 and 15 min, respectively. If both are opened together and at the end of 3 min, the first is closed. How much longer will the cistern take to fill?









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    Part filled by pipe P in 1 min = 1/12
    Part filled by pipe Q in 1 min = 1/15
    Part filled by both pipes in 1 min = 1/12 + 1/15 + = (5 + 4)/60 = 9/60
    Now, Part filled by both pipes in 3 min = (3 x 9)/60 = 27/60 = 9/20
    ∴ Remaining part = 1 - 9/20 = 11/20

    Correct Option: A

    Part filled by pipe P in 1 min = 1/12
    Part filled by pipe Q in 1 min = 1/15
    Part filled by both pipes in 1 min = 1/12 + 1/15 + = (5 + 4)/60 = 9/60
    Now, Part filled by both pipes in 3 min = (3 x 9)/60 = 27/60 = 9/20
    ∴ Remaining part = 1 - 9/20 = 11/20
    Let the remaining part is filled by pipe Q in T min.
    Then, T/15 = 11/20
    T = (15 x 11)/20 = (3 x 11)/4
    = 33/4 = 84/4 min



  1. A, B and C are three pipes connected to a tank. A and B together fill the tank in 6 h, B and C together fill the tank in 10 h and A and C together fill the tank in 12 h. in how much time A, B and C fill up the tank together?









  1. View Hint View Answer Discuss in Forum

    Part filled by ( A + B ) in 1 h = 1/6
    Part filled by ( B + C ) in 1 h = 1/10
    Part filled by ( A + C ) in 1 h = 1/12
    ∴ Part filled by 2 ( A + B + C ) in 1 h = 1/6 +1/10 + 1/12 = (10 + 6 + 5)/60 = 21/60 = 7/20
    ∴ Part filled by ( A + B + C ) in 1 h = 7/(2 x 20) = 7/40

    Correct Option: D

    Part filled by ( A + B ) in 1 h = 1/6
    Part filled by ( B + C ) in 1 h = 1/10
    Part filled by ( A + C ) in 1 h = 1/12
    ∴ Part filled by 2 ( A + B + C ) in 1 h = 1/6 +1/10 + 1/12 = (10 + 6 + 5)/60 = 21/60 = 7/20
    ∴ Part filled by ( A + B + C ) in 1 h = 7/(2 x 20) = 7/40
    ∴ Required time 40/7 = 55/7 h