We find LCM of 20, 28, 32 and 35

∴ LCM = 2 × 2 × 5 × 7 × 8 = 1120
∴ Required number = 5834 – LCM of 20, 28, 32 and 35

Correct Option: B

We find LCM of 20, 28, 32 and 35

∴ LCM = 2 × 2 × 5 × 7 × 8 = 1120
∴ Required number = 5834 – LCM of 20, 28, 32 and 35
∴ Required number = 5834 – 1120 = 4714

The LCM of 6, 12 and 18 = 36 = 6²

Correct Option: D

The LCM of 6, 12 and 18 = 36 = 6² = 36
Hence , required answer is 36.

LCM of p and q = 161
∴ pq = 23 × 7
∴ p = 23; q = 7
∴ 3q – p = 3 × 7 – 23

Correct Option: A

LCM of p and q = 161
∴ pq = 23 × 7
∴ p = 23; q = 7
∴ 3q – p = 3 × 7 – 23
The value of (3q – p) = 21 – 23 = – 2

We find LCM of 60 ,

∴ 60 = 2 × 2 × 3 × 5
i.e., Numbers = 2, 3, 4 and 5

Correct Option: B

We find LCM of 60 ,

∴ 60 = 2 × 2 × 3 × 5
i.e., Numbers = 2, 3, 4 and 5
∴ Required sum = 2 + 3 + 4 + 5 = 14

Required answer = LCM of 36, 40 and 48 seconds

∴ LCM = 2 × 2 × 2 × 2 × 3 × 3 × 5 = 720

Correct Option: B

Required answer = LCM of 36, 40 and 48 seconds
= 720 seconds