Signals and systems electrical engineering miscellaneous


Signals and systems electrical engineering miscellaneous

  1. Let X(z) =
    1
    1 - z-3

    be the Z-transform of a causal signal x[n]. Then, the values of x[2] and x[3] are









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    Given x(z) =
    1
    1 - z–3

    x(z) can be written as = 1 + z–3 + z–6 + 2–9
    Now x[2] correspond to coefficient z–2 = 0
    and x [3] correspond to coefficient of z–3 = 1

    Correct Option: B

    Given x(z) =
    1
    1 - z–3

    x(z) can be written as = 1 + z–3 + z–6 + 2–9
    Now x[2] correspond to coefficient z–2 = 0
    and x [3] correspond to coefficient of z–3 = 1


  1. The functi on shown in the figure can be represented as









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    NA

    Correct Option: A

    NA



  1. For a periodic square wave, which one of the following statements is TRUE?









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    For a Periodic square wave, the fourier series coefficients exist and reconstruction converges at most points.

    Correct Option: C

    For a Periodic square wave, the fourier series coefficients exist and reconstruction converges at most points.


  1. x(t) is nonzero only for Tx < t < T'x, and similarly, y(t) is nonzero only for Ty < t < T'y. Let z(t) be convolution of x(t) and y(t). Which one of the following statements is TRUE?









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    Given that z(t) is x(t)* y(t)
    Range of z(t) is [sum of lower limits of x(t) and y(t) to sum of upper limit of x(t) and y(t)].
    Tx + Ty < t < Tx + Ty

    Correct Option: C

    Given that z(t) is x(t)* y(t)
    Range of z(t) is [sum of lower limits of x(t) and y(t) to sum of upper limit of x(t) and y(t)].
    Tx + Ty < t < Tx + Ty



  1. Let S be the set of points in the complex plane corresponding to the unit circle. (That i s, S = {z: | z| = 1}. Consider the function f(z) = zz* where z* denotes the complex conjugate of z. The f(z) maps S to which one of the following in the complex plane









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    ƒ(Z) = Z.Z*
    where Z* is conjugate of Z
    ∴ ƒ(Z) = | Z|²
    = 1 + i.0
    ∴ ƒ(Z) maps S to the point (1, 0) in the complex plane

    Correct Option: C

    ƒ(Z) = Z.Z*
    where Z* is conjugate of Z
    ∴ ƒ(Z) = | Z|²
    = 1 + i.0
    ∴ ƒ(Z) maps S to the point (1, 0) in the complex plane