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Let X(z) = 1 1 - z-3
be the Z-transform of a causal signal x[n]. Then, the values of x[2] and x[3] are
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- 0 and 0
- 0 and 1
- 1 and 0
- 1 and 1
Correct Option: B
| Given x(z) = | ||
| 1 - z–3 |
x(z) can be written as = 1 + z–3 + z–6 + 2–9
Now x[2] correspond to coefficient z–2 = 0
and x [3] correspond to coefficient of z–3 = 1
