Signals and systems electrical engineering miscellaneous
- The response of an initially relaxed linear circuit to a signal Vs is e– 2tu(t). If the signal is changed to (Vs + 2(dVs/dt), then response will be
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When the excitation of alinear system is differential, the output also is the differentiation of previous output
∴ Response = e– 2t u(t) + 2 d/dt[e2t u(t)] = – 3e– 2t u(t)Correct Option: B
When the excitation of alinear system is differential, the output also is the differentiation of previous output
∴ Response = e– 2t u(t) + 2 d/dt[e2t u(t)] = – 3e– 2t u(t)
- If system is initially at rest, the response to a unit step u(t) is given by 1/2 (1 – e– 2t) The response to a signal u(t) + 2δ (t) is given by
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Here C(t) = 1 (1 - e-2t, R(s) = 1 2 s i.e C(s) = 1 1 - 1 = 1 2 s s + 2 s(s + 2) H(s) = L(s) R(s) u(s) = 1 s + 2 Now for R'(s) = 1 + 2 s ⇒ C'(s) = 1 × 1 + 2 = 2s + 1 = A + B (s + 2) s s(s + 2) s s + 2 Correct Option: A
Here C(t) = 1 (1 - e-2t, R(s) = 1 2 s i.e C(s) = 1 1 - 1 = 1 2 s s + 2 s(s + 2) H(s) = L(s) R(s) u(s) = 1 s + 2 Now for R'(s) = 1 + 2 s ⇒ C'(s) = 1 × 1 + 2 = 2s + 1 = A + B (s + 2) s s(s + 2) s s + 2
- The Laplace transform of sinh at is
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NA
Correct Option: A
NA
- The Laplace transform of f(t) = t is given by
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NA
Correct Option: A
NA
- Laplace transform of t sin at is
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NA
Correct Option: A
NA