Signals and systems electrical engineering miscellaneous
- Given a sequence x[n], to generate the sequence y[n] = x[3 – 4n].Which one of the following procedures would be correct?
-
View Hint View Answer Discuss in Forum
On picking up fourth sample of x [n], we get
V1 [n] = x [4n]
On time reversing V1 [n], we get
V2 [n] = x [– 4n]
Now on delaying V2 [n] by 3 samples, we get
y[n] = x [3 – 4n]Correct Option: D
On picking up fourth sample of x [n], we get
V1 [n] = x [4n]
On time reversing V1 [n], we get
V2 [n] = x [– 4n]
Now on delaying V2 [n] by 3 samples, we get
y[n] = x [3 – 4n]
- The impulse response of a causal linear timeinvariant system is given as h(t).
Now consider the following two statements:
Statement I: Principle of superposition holds
Statement II: h(t) = 0 for t < 0 Which one of the following statements is correct?
-
View Hint View Answer Discuss in Forum
For causal linear time invariant system
(1) Superposition principal holds true
(2) for impulse input, h(t) = 0 for t < 0.Correct Option: D
For causal linear time invariant system
(1) Superposition principal holds true
(2) for impulse input, h(t) = 0 for t < 0.
- A signal e-αt sin(ωt) is the input to a Linear Time Invariant system. Given K and φ are constants, the output of the system will be of the form Ke-βt sin(vt + φ), where
-
View Hint View Answer Discuss in Forum
Frequency (v) of output must be equal to input frequency (ω),while β will depend on system parameters and need not be equal to α.Correct Option: A
Frequency (v) of output must be equal to input frequency (ω),while β will depend on system parameters and need not be equal to α.
- The Fourier Series coefficients, of a periodic signal x(t),expressed as
are given by
a–2 = – j1; a–2 = 0.5 + j0.2; ao = j2; a1 = 0.5 – j0.2; a2= 2+ j1; and ak = 0; for |k| > 2.
Which of the following is true?
-
View Hint View Answer Discuss in Forum
So imaginary part of x(t) is constant = 2
x(t) has finite energy because only finite coefficients are zero.Correct Option: A
So imaginary part of x(t) is constant = 2
x(t) has finite energy because only finite coefficients are zero.
- A cascade of 3 Liner Time Invariant systems is causal and unstable. From this, we conclude that
-
View Hint View Answer Discuss in Forum
If h1 (t), h2 (t) and h3 (t) are the impulse response of the three LTI-systems, then
Overall response of the system is h(t) = G1 (t) × G2 (t) × G3 (t)
Assuming t1, t2, t3 are the initial points of three systems,
then, by convolution theorem, initial point for The combined system t = t1 + t2 + t3
As the entire system is causal, therefore h(t) > 0 for t > 0
For this condition, t > 0 to be true, at least one of the time t1, t2, t3 must be greater than zero.
i.e. one of the system must be causal. As far as stability is concerned, if the system becomes unstable, the entire system will be unstable.Correct Option: B
If h1 (t), h2 (t) and h3 (t) are the impulse response of the three LTI-systems, then
Overall response of the system is h(t) = G1 (t) × G2 (t) × G3 (t)
Assuming t1, t2, t3 are the initial points of three systems,
then, by convolution theorem, initial point for The combined system t = t1 + t2 + t3
As the entire system is causal, therefore h(t) > 0 for t > 0
For this condition, t > 0 to be true, at least one of the time t1, t2, t3 must be greater than zero.
i.e. one of the system must be causal. As far as stability is concerned, if the system becomes unstable, the entire system will be unstable.