Physical electronics devices and ics miscellaneous


Physical electronics devices and ics miscellaneous

Physical Electronics Devices and ICs

  1. For the Zener regulator circuit shown below, the range of input voltage for the Zener diode to remain in ‘ON’—











  1. View Hint View Answer Discuss in Forum

    The given circuit (i.e., fig)

    From figure, VZ = VL = Vi(min) ×
    2K
    2K + 0·25K

    or 20 = Vi(min) ×
    2
    2·25

    or Vi(min) = 20 ×
    2.25
    = 22·5V
    2

    Given, IZM = IZ(max) = 50 mA
    IL =
    20
    = 10 mA
    2K

    IS(max) = IZ(max) + IL
    = 50 mA + 10 mA = 60 mA
    Since, IS(max) =
    Vi(max) – VZ
    0·25 Kπ

    or Vi(max) = IS(max) × 0·25 Kπ + VZ = 60 mA × 0·25 Kπ + 20 V
    or Vi(max) = 15V + 20V = 35V
    Therefore the range of input voltage 22·5V < Vi < 35V
    Hence alternative (B) is the correct choice.


    Correct Option: B

    The given circuit (i.e., fig)

    From figure, VZ = VL = Vi(min) ×
    2K
    2K + 0·25K

    or 20 = Vi(min) ×
    2
    2·25

    or Vi(min) = 20 ×
    2.25
    = 22·5V
    2

    Given, IZM = IZ(max) = 50 mA
    IL =
    20
    = 10 mA
    2K

    IS(max) = IZ(max) + IL
    = 50 mA + 10 mA = 60 mA
    Since, IS(max) =
    Vi(max) – VZ
    0·25 Kπ

    or Vi(max) = IS(max) × 0·25 Kπ + VZ = 60 mA × 0·25 Kπ + 20 V
    or Vi(max) = 15V + 20V = 35V
    Therefore the range of input voltage 22·5V < Vi < 35V
    Hence alternative (B) is the correct choice.



  1. In a voltage regulator network with fixed RL and R, what element dictates the minimum level of source voltage?









  1. View Hint View Answer Discuss in Forum

    In a voltage regular network with fixed RL and R
    ∴ I = or Vi = I R + VZ
    Thus, VZ dictates the minimum level of source voltage.

    Correct Option: A

    In a voltage regular network with fixed RL and R
    ∴ I = or Vi = I R + VZ
    Thus, VZ dictates the minimum level of source voltage.



  1. With this Zener diode in its ‘‘on state’’. What is the level of IZ for the maximum load resistance?











  1. View Hint View Answer Discuss in Forum

    Since given that Zener diode in its ‘ON’ state
    so, VL = VZv = 10 V

    IR =
    Vi – VZ
    =
    (50 – 10) V
    = 40 mA
    R1 kΩ

    IL(min) = IR – IZM = 40 – 32 = 8 mA
    We know that for maximum load resistance load current should be minimum i.e.
    RL(max) =
    VZ
    IL (min)

    Hence IZ should be equal to IZM.


    Correct Option: D

    Since given that Zener diode in its ‘ON’ state
    so, VL = VZv = 10 V

    IR =
    Vi – VZ
    =
    (50 – 10) V
    = 40 mA
    R1 kΩ

    IL(min) = IR – IZM = 40 – 32 = 8 mA
    We know that for maximum load resistance load current should be minimum i.e.
    RL(max) =
    VZ
    IL (min)

    Hence IZ should be equal to IZM.



  1. Calculate IL and IZ.—











  1. View Hint View Answer Discuss in Forum

    First step to check whether zener diode in breakdown mode or not

    VL = V i
    5K
    =
    16 × 5
    13.33V
    5k + 1 kΩ6

    ∴ VL > VZ, So Zener diode in break down mode
    Therefore,
    IL =
    VL
    =
    VZ
    =
    10V
    RLRL5 kΩ

    or IL = 2mA
    I =
    Vi – VZ
    =
    16 – 10
    = 6 mA
    R1 kΩ

    Now, IZ = I – IL = 6 – 2 = 4mA.
    Hence alternative (D) is the correct choice.


    Correct Option: D

    First step to check whether zener diode in breakdown mode or not

    VL = V i
    5K
    =
    16 × 5
    13.33V
    5k + 1 kΩ6

    ∴ VL > VZ, So Zener diode in break down mode
    Therefore,
    IL =
    VL
    =
    VZ
    =
    10V
    RLRL5 kΩ

    or IL = 2mA
    I =
    Vi – VZ
    =
    16 – 10
    = 6 mA
    R1 kΩ

    Now, IZ = I – IL = 6 – 2 = 4mA.
    Hence alternative (D) is the correct choice.




  1. In the breakdown region, a Zener diode behaves like a—









  1. View Hint View Answer Discuss in Forum

    In the breakdown region, a zener diode behaves like a constant voltage source.

    Correct Option: A

    In the breakdown region, a zener diode behaves like a constant voltage source.