Physical electronics devices and ics miscellaneous
- For the Zener regulator circuit shown below, the range of input voltage for the Zener diode to remain in ‘ON’—
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The given circuit (i.e., fig)
From figure, VZ = VL = Vi(min) × 2K 2K + 0·25K or 20 = Vi(min) × 2 2·25 or Vi(min) = 20 × 2.25 = 22·5V 2
Given, IZM = IZ(max) = 50 mAIL = 20 = 10 mA 2K
IS(max) = IZ(max) + IL
= 50 mA + 10 mA = 60 mASince, IS(max) = Vi(max) – VZ 0·25 Kπ
or Vi(max) = IS(max) × 0·25 Kπ + VZ = 60 mA × 0·25 Kπ + 20 V
or Vi(max) = 15V + 20V = 35V
Therefore the range of input voltage 22·5V < Vi < 35V
Hence alternative (B) is the correct choice.Correct Option: B
The given circuit (i.e., fig)
From figure, VZ = VL = Vi(min) × 2K 2K + 0·25K or 20 = Vi(min) × 2 2·25 or Vi(min) = 20 × 2.25 = 22·5V 2
Given, IZM = IZ(max) = 50 mAIL = 20 = 10 mA 2K
IS(max) = IZ(max) + IL
= 50 mA + 10 mA = 60 mASince, IS(max) = Vi(max) – VZ 0·25 Kπ
or Vi(max) = IS(max) × 0·25 Kπ + VZ = 60 mA × 0·25 Kπ + 20 V
or Vi(max) = 15V + 20V = 35V
Therefore the range of input voltage 22·5V < Vi < 35V
Hence alternative (B) is the correct choice.
- In a voltage regulator network with fixed RL and R, what element dictates the minimum level of source voltage?
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In a voltage regular network with fixed RL and R
∴ I = or Vi = I R + VZ
Thus, VZ dictates the minimum level of source voltage.Correct Option: A
In a voltage regular network with fixed RL and R
∴ I = or Vi = I R + VZ
Thus, VZ dictates the minimum level of source voltage.
- With this Zener diode in its ‘‘on state’’. What is the level of IZ for the maximum load resistance?
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Since given that Zener diode in its ‘ON’ state
so, VL = VZv = 10 VIR = Vi – VZ = (50 – 10) V = 40 mA R 1 kΩ
IL(min) = IR – IZM = 40 – 32 = 8 mA
We know that for maximum load resistance load current should be minimum i.e.RL(max) = VZ IL (min)
Hence IZ should be equal to IZM.Correct Option: D
Since given that Zener diode in its ‘ON’ state
so, VL = VZv = 10 VIR = Vi – VZ = (50 – 10) V = 40 mA R 1 kΩ
IL(min) = IR – IZM = 40 – 32 = 8 mA
We know that for maximum load resistance load current should be minimum i.e.RL(max) = VZ IL (min)
Hence IZ should be equal to IZM.
- Calculate IL and IZ.—
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First step to check whether zener diode in breakdown mode or not
VL = V i 5K = 16 × 5 13.33V 5k + 1 kΩ 6
∴ VL > VZ, So Zener diode in break down mode
Therefore,IL = VL = VZ = 10V RL RL 5 kΩ
or IL = 2mAI = Vi – VZ = 16 – 10 = 6 mA R 1 kΩ
Now, IZ = I – IL = 6 – 2 = 4mA.
Hence alternative (D) is the correct choice.Correct Option: D
First step to check whether zener diode in breakdown mode or not
VL = V i 5K = 16 × 5 13.33V 5k + 1 kΩ 6
∴ VL > VZ, So Zener diode in break down mode
Therefore,IL = VL = VZ = 10V RL RL 5 kΩ
or IL = 2mAI = Vi – VZ = 16 – 10 = 6 mA R 1 kΩ
Now, IZ = I – IL = 6 – 2 = 4mA.
Hence alternative (D) is the correct choice.
- In the breakdown region, a Zener diode behaves like a—
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In the breakdown region, a zener diode behaves like a constant voltage source.
Correct Option: A
In the breakdown region, a zener diode behaves like a constant voltage source.