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Calculate IL and IZ.—
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- 2 mA, 0 mA
- 4 mA, 2 mA
- 2 mA, 2 mA
- 2 mA, 4 mA
Correct Option: D
First step to check whether zener diode in breakdown mode or not
| VL = V i | = | 13.33V | 5k + 1 kΩ | 6 |
∴ VL > VZ, So Zener diode in break down mode
Therefore,
| IL = | = | = | RL | RL | 5 kΩ |
or IL = 2mA
| I = | = | = 6 mA | R | 1 kΩ |
Now, IZ = I – IL = 6 – 2 = 4mA.
Hence alternative (D) is the correct choice.
