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  1. If sin A =
    3
    and cos B =
    12
    , what is the value of
    tanA - tanB
    5131 + tanA tanB

    ; it being given that A and B are acute angles?
    1. 15
      63
    2. 19
      63
    3. 17
      65
    4. 16
      63
Correct Option: D

sin A =
3
5

∴ cos A = √1 - sin²A
= √ 1 -
9
25

= √
25 - 9
= √
16
=
4
25255

cos B =
12
13

sin B = √1 - cos²B
= √ 1 -
144
169

= √ 1 -
12
²
13

= √ 1 -
144
= √
169 - 144
= √
25
=
5
1691691695

∴ tanA =
1
=
sinA =
5
3
cosA
4
4
5

∴ tanB =
5
=
sinB =
13
5
cosB
12
12
13

3
-
5
tanB - tanB = 412
1 + tanA.tanB 1 +
3
.
5
412

=
9 - 5
12
1 +
5
16

=
1
3
21
16

=
1
×
16
=
16
32163



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