In ∆ABC, D is the mid-point of BC. Length AD is 27

Home » Aptitude » Plane Geometry » Question

In ∆ABC, D is the mid-point of BC. Length AD is 27 cm. N is a point in AD such that the length of DN is 12 cm. The distance of N from the centroid of ∆ ABC is equal to

On the basis of given in question , we draw a figure triangle ABC ,

AD = 27 cm
Centroid = O
From figure we know that , AO : OD = 2 : 1

∴ OD =		1	AD
		3

OD =		1	× 27 = 9 cm
		3

Given , ND = 12 cm
∴ ON = DN – OD = 12 – 9 = 3 cm