In a ∆ ABC, AB = BD , ∠B = 70° and ∠C

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As per the given in question , we draw a figure of triangle ABC

	AB	=	BD
	AC		DC

∴ AD is the bisector of ∠A.

∴ ∠BAD =	1	(∠BAC)
	2

∴ ∠BAD =	180 - ∠B - ∠C
	2

∠BAD =	180 - 70 - 50	=	60	= 30°
	2		2

In a ∆ ABC,	AB	=	BD	, ∠B = 70° and ∠C = 50°, thrn ∠ BAD = ?
	AC		DC