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In ∆ ABC, two points D and E are taken on the lines AB and BC respectively in such a way that AC is parallel to DE. Then ∆ ABC and ∆ DBE are
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- similar only if D lies outside the line segment AB
- congruent only if D lies outside the line segment AB
- always similar
- always congruent
- similar only if D lies outside the line segment AB
Correct Option: C
According to question , we draw a figure triangle ABC in which two points D and E are taken on the lines AB and BC respectively in such a way that AC is parallel to DE ,
In ∆ ABC and ∆ DBE,
DE || AC
∴ ∠BAC = ∠BDE
∠BCA = ∠BED
∴ By AA–similarity
∆ ABC ~ ∆ DBE
From above it is clear that ∆ ABC and ∆ DBE are congruent triangles .