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Inside a triangle ABC, a straight line parallel to BC intersects AB and AC at the point P and Q respectively. If AB = 3 PB, then PQ : BC is
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- 1 : 3
- 3 : 4
- 1 : 2
- 2 : 3
- 1 : 3
Correct Option: D
As per the given in question , we draw a figure triangle ABC 
Let PB = x ⇒ AB = 3x and AP = 3x – x = 2x
In ∆ ABC, PQ || BC
⇒ ∆ APQ ~ ∆ ABC
| ⇒ | = | = | = | = 2 : 3 | ||||
| AB | BC | 3x | 3 |
