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The perimeters of two similar triangles ∆ ABC and ∆ PQR are 36 cm and 24 cm respectively. If PQ = 10 cm, then AB is
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- 15 cm
- 12 cm
- 14 cm
- 26 cm
- 15 cm
Correct Option: A
As per the given in question , we draw figures of two similar triangles PQR and ABC
In similar triangles ∆ ABC and ∆ PQR,
| = | = | ||||
| PQ | QR | PR |
| = | ||
| PQ + QR + PR |
| ⇒ | = | = | |||
| 10 | 24 | 2 |
| ⇒ AB = | × 10 = 15 cm. | |
| 2 |
