Home » Aptitude » Plane Geometry » Question
  1. In ∆ ABC, E and D are points on sides AB and AC respectively such that ∠ABC = ∠ADE. If AE = 3 cm, AD = 2 cm and EB = 2 cm, then length of DC is
    1. 4 cm
    2. 4.5 cm
    3. 5.0 cm
    4. 5.5 cm
Correct Option: D

As per the given in question , we draw a figure triangle ABC

Here , AE = 3 cm, AD = 2 cm and EB = 2 cm,
In ∆ ADE and ∆ ABC,
∠ABC = ∠ADE
∠A = ∠A
∴ ∆ ABC ~ ∆ ADE

AB
=
BC
=
AC
ADDEAE

AB + EB
=
AC
ADAE

3 + 2
=
AC
23

5
=
AC
23

⇒ 2AC = 5 × 3 ⇒ AC =
15
2

⇒ DC = AC – AD
DC =
15
- 2 =
15 - 4
=
11
222

DC = 5.5 cm



Your comments will be displayed only after manual approval.