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					 In ∆ ABC, E and D are points on sides AB and AC respectively such that ∠ABC = ∠ADE. If AE = 3 cm, AD = 2 cm and EB = 2 cm, then length of DC is
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                        -  4 cm 
 
-  4.5 cm 
 
-  5.0 cm 
 
- 5.5 cm
 
-  4 cm 
Correct Option: D
As per the given in question , we draw a figure  triangle ABC 
Here , AE = 3 cm, AD = 2 cm and EB = 2 cm,
In ∆ ADE and ∆ ABC, 
∠ABC = ∠ADE 
∠A = ∠A 
∴ ∆ ABC ~ ∆ ADE
| ∴ | = | = | |||
| AD | DE | AE | 
| ∴ | = | ||
| AD | AE | 
| ⇒ | = | ||
| 2 | 3 | 
| ⇒ | = | ||
| 2 | 3 | 
| ⇒ 2AC = 5 × 3 ⇒ AC = | |
| 2 | 
⇒ DC = AC – AD
| DC = | - 2 = | = | |||
| 2 | 2 | 2 | 
DC = 5.5 cm
 
	