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In a ∆ ABC, D and E are two points on AB and AC respectively such that DE || BC, DE bisects the ∆ ABC in two equal areas. Then the ratio DB : AB is
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- 1 : √2
- 1 : 2
- ( √2 – 1) : √2
- √2 : 1
- 1 : √2
Correct Option: C
According to question , we draw a figure of triangle ABC in which D and E are two points on AB and AC respectively such that DE || BC , 
Given , ∆ ADE = ☐ BDEC
⇒ ∆ 2ADE = ∆ ABC
DE || BC
∴ ∆ ADE ~ ∆ ABC
| ∴ | = | = | |||
| ∆ ABC | 2 | AB² |
| ⇒ | = √2 | |
| AD |
| ⇒ | - 1 = √2 - 1 | |
| AD |
| ⇒ | = √2 - 1 | |
| AD |
| ⇒ | = √2 - 1 | |
| AD |
| ∴ | = | × | = | ||||
| AB | AD | AB | √2 |