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∆ ABC and ∆ DEF are similar. Also ∠A = ∠D and ∠B = ∠E. If 4AB = DE and BC = 12 cm, then EF is equal to
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- 3 cm
- 24 cm
- 16 cm
- 48 cm
- 3 cm
Correct Option: D
As per the given in question , we draw figures of two similar triangles ABC and DEF
Given that , ∠A = ∠D and ∠B = ∠E and BC = 12 cm
∆ ABC ~ ∆ DEF and 4AB = DE
⇒ | = | ||
DE | 4 |
∴ | = | ||
DE | EF |
⇒ | = | ||
4 | EF |
⇒ EF = 48 cm.