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  1. ∆ ABC and ∆ DEF are similar. Also ∠A = ∠D and ∠B = ∠E. If 4AB = DE and BC = 12 cm, then EF is equal to
    1. 3 cm
    2. 24 cm
    3. 16 cm
    4. 48 cm
Correct Option: D

As per the given in question , we draw figures of two similar triangles ABC and DEF


Given that , ∠A = ∠D and ∠B = ∠E and BC = 12 cm
∆ ABC ~ ∆ DEF and 4AB = DE

AB
=
1
DE4

AB
=
BC
DEEF

1
=
12
4EF

⇒ EF = 48 cm.



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