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If PA and PB are two tangents to a circle with centre O such that ∠AOB = 110°, then ∠APB is
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- 90°
- 70°
- 60°
- 55°
- 90°
Correct Option: B
As per the given in question , we draw a figure of a circle with centre O in which PA and PB are two tangents
Given , ∠AOB = 110°
∠OAP = 90°
∠OBP = 90°
∴ ∠APB + ∠AOB + ∠OAP + ∠OBP = 360°
⇒ ∠APB + 110° + 90° + 90° = 360°
⇒ ∠APB = 180° – 110° = 70°