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Let P and Q be two points on a circle with centre O. If two tangents of the circle through P and Q meet at A with ∠PAQ = 48°, then ∠APQ is
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- 96°
- 48°
- 66°
- 60°
- 96°
Correct Option: C
On the basis of question we draw a figure of a circle with centre O , 
Given , ∠ PAQ = 48°
AP = AQ = tangents from the same exterior point.
∴ In ∆ APQ,
∠APQ = ∠AQP
∴ 2 ∠APQ = 180° – 48° = 132°
| ⇒ ∠ APQ = | = 66° | |
| 2 |
