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Two circles of diameters 10 cm and 6 cm have the same centre. A chord of the larger circle is a tangent of the smaller one. The length of the chord is
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- 4 cm.
- 8 cm.
- 6 cm.
- 10 cm.
- 4 cm.
Correct Option: B
As per the given in question , we draw a figure of two circles of diameters 10 cm and 6 cm
OE ⊥ AB ; OE ⊥ CD
OE = OA = OB = 3 cm
OC = OD = 5 cm
From ∆ EOC ,
∴ CE² = OC² – OE²
⇒ 5² – 3² = 25 – 9 = 16
⇒ CE = √16 = 4 cm
∴ CD = 2CE = 2 × 4 = 8 cm
