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∆ ABC is inscribed in a circle so that BC is diameter. The tangent at a point C intersects BA when produced at a point D. If ∠ABC = 36° then the value of ∠ADC is
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- 36°
- 44°
- 48°
- 54°
- 36°
Correct Option: D
According to question , we draw a figure of ∆ ABC in which inscribed in a circle 
The angle at the circumference of a semi–circle is a right angle.
∴ ∠BAC = 90°
∠ABC = 36°
∴ ∠ACB = 90° – 36° = 54°
∠BCD = 90°
∴ ∠ACD = 90° – 54° = 36°
∠DAC = 90°
∴ ∠ADC = 90° – 36° = 54°
