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PQ is a tangent to the circle at T. If TR = TS where R and S are points on the circle and ∠RST = 65°, the ∠PTS = ?
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- 65°
- 130°
- 115°
- 55°
- 65°
Correct Option: C
On the basis of question we draw a figure of a circle with centre O and PQ is a tangent
Here , TR = TS
∠SRT = ∠TSR = 65°
∴ ∠STR = 180° – 130° = 50°
∴ ∠PTR = ∠STQ = | = 65° | |
2 |
∴ ∠PTS = 65° + 50° = 115°