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There are two equal circles of radius 3 cm each and distance between their centres is 10 cm. The length of one of their transverse common tangents is
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- 7 cm
- 9 cm
- 10 cm
- 8 cm
- 7 cm
Correct Option: D
As per the given in question , we draw a figure of two equal circles
Transverse common tangent = √d² - (r1 + r2)²
Transverse common tangent = √10² - (3 + 3)²
[ r1 = r2 = 3 cm.]
Transverse common tangent = √100 - 36
Transverse common tangent = √64 = 8 cm.