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					 There are two equal circles of radius 3 cm each and distance between their centres is 10 cm. The length of one of their transverse common tangents is
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                        -  7 cm 
 
-  9 cm 
 
-  10 cm 
 
- 8 cm
 
-  7 cm 
Correct Option: D
As per the given in question , we draw a figure of two equal circles 
Transverse common tangent = √d² - (r1 + r2)²
Transverse common tangent = √10² - (3 + 3)² 
[ r1 = r2 = 3 cm.] 
Transverse common tangent  = √100 - 36 
Transverse common tangent  = √64 = 8 cm.
 
	