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O is the circumcentre of a triangle ∆ ABC. The point A and th chord BC are on the opposite side of O. If ∠BOC = 150°. Then the angle ∠BAC is :
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- 65°
- 60°
- 70°
- 75°
- 65°
Correct Option: D
According to question , we draw a figure of triangle ABC circumscribes a circle with centre O
Given , ∠BOC = 150°
As we know that Angle subtended at the centre of a circled by an arc is twice to that at the circumference.
∴ ∠BOC = 2∠BAC
| ⇒ ∠BAC = | = 75° | |
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