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					 From the circumcentre I of the triangle ABC, perpendicular ID is drawn on BC. If ∠BAC = 60°, then the value of ∠BID is :
 
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                        -  60° 
 
-  80° 
 
-  75° 
 
- 45°
 
-  60° 
Correct Option: A
As per the given in question , we draw a figure of  a triangle ABC 
Here , ∠BAC = 60° 
BI = IC = in–radius 
∴ Angle subtended by arc AC at the centre = 2 × ∠BAC 
Angle subtended by arc AC at the centre = 2 × 60° = 120°
| ∴ ∠BID = ∠DIC = | = 60° | |
| 2 | 
 
	