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From the circumcentre I of the triangle ABC, perpendicular ID is drawn on BC. If ∠BAC = 60°, then the value of ∠BID is :
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- 60°
- 80°
- 75°
- 45°
- 60°
Correct Option: A
As per the given in question , we draw a figure of a triangle ABC
Here , ∠BAC = 60°
BI = IC = in–radius
∴ Angle subtended by arc AC at the centre = 2 × ∠BAC
Angle subtended by arc AC at the centre = 2 × 60° = 120°
∴ ∠BID = ∠DIC = | = 60° | |
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