In a ∆ABC, AB² + AC² = BC² and BC = √2AB, then ∠ABC is :
30°
45°
60°
90°
Correct Option: B
As per the given in question , we draw a figure of a ∆ABC, Here , AB² + AC² = BC² and BC = √2AB, AB² + AC² = BC² ⇒ ∠BAC = 90° ⇒ AB² + AC² = 2AB² ⇒ AB² = AC² ⇒ AB = AC ∴ ∠ABC = ∠ACB = 45°