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A straight line parallel to BC of ∆ABC intersects AB and AC at points P and Q respectively. AP = QC, PB= 4 units and AQ = 9 units, then the length of AP is :
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- 25 units
- 3 units
- 6 units
- 6.5 units
- 25 units
Correct Option: C
On the basis of question we draw a figure of a ∆ABC in which a straight line parallel to BC intersects AB and AC at points P and Q respectively.
Given , AP = QC, PB= 4 units and AQ = 9 units
PQ || BC
∴ | = | ||
AB | AC |
⇒ | = | ||
AP | AQ |
⇒ | = | ||
AP | AQ |
⇒ | = | = | |||
AP | AQ | AQ |
⇒ AP² = PB. AQ = 4 × 9 = 36
∴ AP = 6 units