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O is the centre and arc ABC subtends an angle of 130° at O. AB is extended to P. Then ∠PBC is
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- 75°
- 70°
- 65°
- 80°
- 75°
Correct Option: C
On the basis of question we draw a figure of a circle with centre O and arc ABC subtends an angle of 130° at O , 
Given that , ∠AOC = 130°
| ⇒ ∠ADC = | × 130° = 65° | |
| 2 |
∠PBC = ∠ADC = 65°
