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					 Internal bisectors of angles ∠B and ∠C of a triangle ABC meet at O. If ∠BAC = 80°, then the value of ∠BOC is
 
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                        -  120° 
 
-  140° 
 
-   110° 
 
- 130°
 
-  120° 
Correct Option: D
As per the given in question , we draw a figure of a triangle ABC in which ∠B and ∠C are internal bisectors of angles of triangle   
Here , ∠BAC = 80° 
In ∆ ABC ,
As we know that , ∠A + ∠B + ∠C = 180°
∴ ∠B + ∠C = 180° – 80° = 100° 
| + | = 50° | |||
| 2 | 2 | 
In ∆ BOC ,
⇒ ∠OBC + ∠OCB = 50°
∴ ∠BOC = 180° – 50° = 130°
 
	