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					 PQRS is a cyclic quadrilateral. The bisectors of the angles ∠P and ∠R meet the circle ABCD at A and B respectively. If the radius of the circle be r units, then AB = ?
 
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                        -  r 
 
- 2r
-  2 r 3 
-  3 r 2 
 
-  r 
Correct Option: B
As per the above given question , we draw a figure of a cyclic quadrilateral  PQRS and the bisectors of the angles ∠P and ∠R meet the circle ABCD at A and B respectively
PQRS is a cyclic quadrilateral. 
∠P + ∠R = 180°
| ⇒ | ∠P + | ∠R = 90° | ||
| 2 | 2 | 
⇒ ∠APS + ∠BRS = 90° ....(i)
But ∠BRS and ∠BPS are angles in the same segment with chord BS.
∴ ∠BRS = ∠BPS .....(ii)
∴ ∠APS + ∠BPS = 90°
⇒ ∠APB = 90°
∴ AB is the diameter.
 
	