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A triangle ABC is inscribed in a circle and the bisectors of the angles A, B and C meet the circumference at P, Q and R respectively. The angles of the triangle PQR respectively are
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90° - A , 90° + A , 90° + C 2 2 2 -
90° + A , 90° - B , 90° - C 2 2 -
90° - A , 90° - B , 90° - C 2 2 2 - None of these
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Correct Option: C
On the basis of given question , we draw a figure of a triangle ABC inscribed in a circle and the bisectors of the angles A, B and C meet the circumference at P, Q and R respectively
∠BQP = ∠BAP
∠BQP = | ||
2 |
∠BQR = ∠BCR
∠BQR = | ∠C | |
2 |
∴ ∠PQR = | (∠A + ∠C) | |
2 |
∴ ∠PQR = | (180° - ∠B) = 90° - | |||
2 | 2 |
∠APR = ∠ACR
∴ ∠PQR = | ∠C | |
2 |
Also,∠APR = ∠ABQ
⇒ ∠APR = | ∠B | |
2 |
∴ ∠APQ + ∠APR = | (∠B + ∠C) | |
2 |
⇒ ∠QPR = | (180° - ∠A) = 90° - | ||
2 | 2 |
Similarly,
∠QRP = 90 - | |
2 |