- 
					 A triangle ABC is inscribed in a circle and the bisectors of the angles A, B and C meet the circumference at P, Q and R respectively. The angles of the triangle PQR respectively are
- 
                        -   90° - A , 90° + A , 90° + C 2 2 2 
-   90° + A , 90° - B , 90° - C 2 2 
-  90° - A , 90° - B , 90° - C 2 2 2 
- None of these
 
-   
Correct Option: C
On the basis of given question , we draw a figure of a  triangle ABC inscribed in a circle and the bisectors of the angles A, B and C meet the circumference at P, Q and R respectively
∠BQP = ∠BAP
| ∠BQP = | ||
| 2 | 
∠BQR = ∠BCR
| ∠BQR = | ∠C | |
| 2 | 
| ∴ ∠PQR = | (∠A + ∠C) | |
| 2 | 
| ∴ ∠PQR = | (180° - ∠B) = 90° - | |||
| 2 | 2 | 
∠APR = ∠ACR
| ∴ ∠PQR = | ∠C | |
| 2 | 
Also,∠APR = ∠ABQ
| ⇒ ∠APR = | ∠B | |
| 2 | 
| ∴ ∠APQ + ∠APR = | (∠B + ∠C) | |
| 2 | 
| ⇒ ∠QPR = | (180° - ∠A) = 90° - | ||
| 2 | 2 | 
Similarly,
| ∠QRP = 90 - | |
| 2 | 
 
	