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Two chords AB and CD of a circle with centre O intersect at point P within the circle. ∠AOC + ∠BOD = ?
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- ∠APC
- 2∠APC
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3 ∠APC 2 - None of these
- ∠APC
Correct Option: B
According to question , we draw a figure of a circle with centre O in which two chords AB and CD intersect at point P within the circle 
Arc AC subtends ∠AOC at the centre.
∠AOC = 2∠ABC
Similarly, ∠BOD = 2∠BCD
On adding, we get
∠AOC + ∠BOD = 2(∠ABC + ∠BCD) = 2∠APC [∵ ∠APC is the exterior angle]
