If 5 cos θ + 12 sin θ = 13, 0° < θ

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If 5 cos θ + 12 sin θ = 13, 0° < θ < 90°, then the value of sin q is

1. 5
  13
2. - 12
  13
3. 6
  13
4. 12
  13

Correct Option: D

5 cosθ + 12 sinθ = 13

⇒		5	cosθ +	12	sin θ = 1
		13		13

∵ sin²θ + cos²θ = 1

∴ sinθ =		12	. cosθ =	5
		13		13