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If r sin θ = 1, r cos θ = √3 then the value of ( √3 tan θ + 1 ) is :
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- √3
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1 √3 - 1
- 2
Correct Option: D
As we know that from question :-
r sin θ = 1 ......... ( 1 )
r cos θ = √3 ......... ( 2 )
Equation ( 1 ) / Equation ( 2 ) , we get
| ⇒ | sin θ | = tan θ = | 1 |
| cos θ | √3 |
| ⇒ tan θ = tan 30° | ⇒ | θ = 30 ° |
| Now , √3 tan θ + 1 = √3 × tan 30° + 1 |
| √3 tan θ + 1 = | √3 × | 1 | + 1 = 1 + 1 = 2 | √3 |
