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The angle of elevation of a tower from a distance 50 m from its foot is 30°. The height of the tower is :
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- 50 √3 m
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50 m √3 - 75 √3 m
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75 m √3
Correct Option: B
Let us draw the figure from the given question.
Let AB = Tower = h m
GIven :- BC = 50 m
∠ACB = 30°
| In ΔACB , ∴ | tan 30° = | AB | BC |
| ⇒ | 1 | = | AB | ⇔ | AB = | 50 | m |
| √3 | 50 | √3 |
