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When the sun is 30° above the horizontal, the length of shadow cast by a building 50 m high is :
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50 m √3 - 50√3 m
- 25 m
- 25√3 m
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Correct Option: B
Let us draw the figure from the given question.
Let, AB be the building and AC be its shadow.
Then, height of building AB = 50 m and θ = 30°.
| In triangle ACB , cotθ = | AC |
| AB |
| ∴ | AC | = | cot 30° | = | √3 | ⇒ | AC | = √3 |
| AB | 50 |
⇒ AC = 50 √3 m.
Hence , the length of shadow cast by a building 50 m high is 50 √3 m .
