Correct Option: B

∠AGH = ∠DHG (alt. int. angles)

⇒	1	∠AGH	=	1	∠DHG	= 180
	2			2

Thus, lines GM and HL are intersected by a transversal GH at G and H respectively such that pair of alternate angles are equal, i.e.,
∴ ∠HGM = ∠GHL
∴ GM || HL
Similarly, GL || HM
So, GMHL is a ||gm.
Since AB || CD and EF is a transversal
∴ ∠BGH + ∠DHG = 180° [co-interior angles]

∴	1	∠BGH	+	1	∠DHG	= 90°
	2			2

But ∠LGH + ∠LHG + ∠GLH = 180°
∴ 90° + ∠GLH = 180° ⇒ ∠GLH = 90°
Thus, in ||_gm GMHL, we have ∠GLH = 90°
Hence, GMHL is a rectangle.