Digital electronics miscellaneous


Digital electronics miscellaneous

Digital Electronics

  1. The black box in the figure consists of a minimum complexity circuit that uses only AND, OR and NOT gates. The function f(x, y, z) = 1 whenever x, y are different and 0 otherwise. In addition the 3 inputs x, y, z are never all the same value. Which one of the following equations leads to the correct design for the minimum complexity circuit?











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    NA

    Correct Option: A

    NA


  1. Consider the following statements:
    1. Minimization using Karnaugh map may not provide unique solution.
    2. Redundant grouping in Karnaugh map may result in non-minimized solution.
    3. Don't care states of used in Karnaugh map for minimization, the minimal solution is not obtained.
    Which of the statements given above are correct?









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    With reference to K-map
    ● Minimization using Karnaugh map may not provide unique solution
    ● Redundant grouping in Karnaugh map may result in non-minimized solution.

    Correct Option: D

    With reference to K-map
    ● Minimization using Karnaugh map may not provide unique solution
    ● Redundant grouping in Karnaugh map may result in non-minimized solution.



  1. What is the Boolean expression for the truth table shown below?











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    NA

    Correct Option: A

    NA


  1. Consider the following statements:
    For 3 input variables a, b, c; a Boolean function y = ab + bc + ca represents:
    1. a 3-input majority gate
    2. a 3-input minority gate
    3. Carry output of a full adder
    4. Product circuit for a, b and c
    Which of the above statements are correct?









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    NA

    Correct Option: C

    NA



  1. For the circuit shown in the following figure, I0 – I3 are inputs to the 4: 1 multiplexer, R (MSB) and P and Q are control bits. The output Z can be represented by—











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    The given circuit
    Z = + R + SP + + RSPQ + R + SP + RS (P + + Q)
    or
    Z = + R + SP + + RSPQ + PR + S + PRS + + QRS
    From above K-map, we get
    Z=P + S + PQS + RS + Q


    Correct Option: A

    The given circuit
    Z = + R + SP + + RSPQ + R + SP + RS (P + + Q)
    or
    Z = + R + SP + + RSPQ + PR + S + PRS + + QRS
    From above K-map, we get
    Z=P + S + PQS + RS + Q