Digital electronics miscellaneous
- The black box in the figure consists of a minimum complexity circuit that uses only AND, OR and NOT gates. The function f(x, y, z) = 1 whenever x, y are different and 0 otherwise. In addition the 3 inputs x, y, z are never all the same value. Which one of the following equations leads to the correct design for the minimum complexity circuit?
-
View Hint View Answer Discuss in Forum
NA
Correct Option: A
NA
- Consider the following statements:
1. Minimization using Karnaugh map may not provide unique solution.
2. Redundant grouping in Karnaugh map may result in non-minimized solution.
3. Don't care states of used in Karnaugh map for minimization, the minimal solution is not obtained.
Which of the statements given above are correct?
-
View Hint View Answer Discuss in Forum
With reference to K-map
● Minimization using Karnaugh map may not provide unique solution
● Redundant grouping in Karnaugh map may result in non-minimized solution.Correct Option: D
With reference to K-map
● Minimization using Karnaugh map may not provide unique solution
● Redundant grouping in Karnaugh map may result in non-minimized solution.
- What is the Boolean expression for the truth table shown below?
-
View Hint View Answer Discuss in Forum
NA
Correct Option: A
NA
- Consider the following statements:
For 3 input variables a, b, c; a Boolean function y = ab + bc + ca represents:
1. a 3-input majority gate
2. a 3-input minority gate
3. Carry output of a full adder
4. Product circuit for a, b and c
Which of the above statements are correct?
-
View Hint View Answer Discuss in Forum
NA
Correct Option: C
NA
- For the circuit shown in the following figure, I0 – I3 are inputs to the 4: 1 multiplexer, R (MSB) and P and Q are control bits. The output Z can be represented by—
-
View Hint View Answer Discuss in Forum
The given circuit
Z = + R + SP + + RSPQ + R + SP + RS (P + + Q)
or
Z = + R + SP + + RSPQ + PR + S + PRS + + QRS
From above K-map, we get
Z=P + S + PQS + RS + QCorrect Option: A
The given circuit
Z = + R + SP + + RSPQ + R + SP + RS (P + + Q)
or
Z = + R + SP + + RSPQ + PR + S + PRS + + QRS
From above K-map, we get
Z=P + S + PQS + RS + Q