36. Examine the conditions indicated in figure and find out the faulty gate—
    
    
    

1. 1. (2), (3), (4)

   
   
   

   2. (2), (3), (5)

   
   
   

   3. (2), (4), (5)

   
   
   

   4. (2), (5), (6)

   
   
   

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   NA

   Correct Option: B

   NA

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37. The parity of binary number 11001110

1. 1. is even

   
   
   

   2. is not known

   
   
   

   3. is odd

   
   
   

   4. is as the number of zeros

   
   
   

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   NA

   Correct Option: C

   NA

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38. A network of cascaded inverters is shown. If a HIGH is applied to point A determine the logic levels at point B through F—
    
    
    

1. 1. B = A, C = A, D = A, E = A, F = A

   
   
   

   2. B = A, C = A, D = A, E = A, F = A

   
   
   

   3. B = A, C = A, D = A, E = A, F = A

   
   
   

   4. B = A, C = A, D = A, E = A, F = A

   
   
   

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   B = A
   C = A
   D = A
   E = A
   F = A

   Correct Option: A

   B = A
   C = A
   D = A
   E = A
   F = A

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39. When two n-bit binary numbers are added the sum will contain at the most—

1. 1. n bits

   
   
   

   2. n + 1 bits

   
   
   

   3. n + 2 bits

   
   
   

   4. n + n bits

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: B

   NA

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40. A pulse is applied to each input of a 2 input NAND gate. One pulse goes HIGH at t = 0 and goes back low at t = 1 ms. The other pulse goes HIGH at t = 0·8 ms and goes back low at t = 3 ms. The output pulse can be described as follows—

1. 1. It goes LOW at t = 0 and back HIGH at t = 3 ms

   
   
   

   2. It goes LOW at t = 0·8 ms and back HIGH at t = 3 ms

   
   
   

   3. It goes LOW at t = 0·8 ms and back HIGH at t = 1 ms

   
   
   

   4. It goes LOW at t = 0·8 ms and back LOW at t = 1 ms

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   
   

   Correct Option: C

   NA

   
   

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