Digital electronics miscellaneous Easy Questions and Answers | Page - 53

Digital electronics miscellaneous

With which decoder it is possible to obtain many code conversions?

1. 2 line to 4 line decoder
1. 3 line to 8 line decoder
1. Not possible with any decoder
1. 4 line to 16 line decoder

View Hint View Answer Discuss in Forum

By using 4 line to 16 line decoder it is possible to obtain many code conversion

Correct Option: D

By using 4 line to 16 line decoder it is possible to obtain many code conversion

Which of the following circuits come under the class of combinational logic circuits:
1. Full adder
2. Full subtractor
3. Half adder
4. J-K flip-flop
5. Counter
Select the correct answer from the codes given below—

1. 1 only
1. 3 and 4
1. 4 and 5
1. 1, 2 and 3

View Hint View Answer Discuss in Forum

Combinational logic circuit are:
● Full adder
● Full subtractor
● Half adder

Correct Option: D

Combinational logic circuit are:
● Full adder
● Full subtractor
● Half adder

A digital multiplexer can be used for which of the following?
1. Parallel to serial conversion
2. Many to one switch
3. To generate memory chip select
4. For code conversion
Select the correct answer using the code given below–

1. 1, 3 and 4
1. 2, 3 and 4
1. 1 and 2 only
1. 2 and 3 only

View Hint View Answer Discuss in Forum

A digital multiplexer can be used for
● Parallel to serial conversion
● Many to one switch

Correct Option: C

A digital multiplexer can be used for
● Parallel to serial conversion
● Many to one switch

Consider the following circuit which one of the following gives the function implemented by the MUX based digital circuit?

1. F = C₂ C₁S + C₂C1 ( A + B)
1. F = C₂ C₁ + C₂C₁ + C₂ C₁S + C₂C1 AB
1. F = AB + S
1. F = C₂ C₁+ C2 C₁S + C₂C₁ A B

View Hint View Answer Discuss in Forum

The given circuit
From figure
F = C₂ C₁.1 + C₂C₁( A + B) + C₂ C₁S + C₂ C₁.0
or
F = C₂ C₁ + C₂ C₁S + C₂C₁ A B

Correct Option: D

The given circuit
From figure
F = C₂ C₁.1 + C₂C₁( A + B) + C₂ C₁S + C₂ C₁.0
or
F = C₂ C₁ + C₂ C₁S + C₂C₁ A B

It is required to construct a 2n to 1 multiplexer by using 2 to 1 multiplexers only. How many of 2 to 1 multiplexers are needed?

1. n
1. 22n
1. 2n–1
1. 2n+1

View Hint View Answer Discuss in Forum

To construct a 2ⁿ to 1 multiplexer by using 2 to 1 multiplexer, the number of 2 to 1 multiplex required are 2ⁿ– 1. For example, n = 3 means we have to construct 8 to 1 multiplexer. So we need 2n – 1 = 7, 2 to 1 multiplexer.

Correct Option: A

To construct a 2ⁿ to 1 multiplexer by using 2 to 1 multiplexer, the number of 2 to 1 multiplex required are 2ⁿ– 1. For example, n = 3 means we have to construct 8 to 1 multiplexer. So we need 2n – 1 = 7, 2 to 1 multiplexer.