Digital electronics miscellaneous
- A 0 to 6 count consists of 3 flip-flops and a combination circuit of 2 input gate. The combination consists of—
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Alternative (A) is the most appropriate choice.
Correct Option: A
Alternative (A) is the most appropriate choice.
- A 4-bit binary ripple counter uses flip-flops with a propagation delay time of 25 ns each. The maximum possible time required for change of the state will be—
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Given no. of flip-flops (i.e., no. of bits) = 4 Propagation delay of each flip-flop, tpd = 25 ns. The maximum possible time required for change of the state = 4 × tpd = 4 × 25 = 100 ns.
Correct Option: D
Given no. of flip-flops (i.e., no. of bits) = 4 Propagation delay of each flip-flop, tpd = 25 ns. The maximum possible time required for change of the state = 4 × tpd = 4 × 25 = 100 ns.
- A divide by 72 counter can be realized by using—
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A divide by 72 counter can be realized by using one MOD-12 counter followed by one MOD-6 counter.
Correct Option: C
A divide by 72 counter can be realized by using one MOD-12 counter followed by one MOD-6 counter.
- A 4-bit modulo-16 ripple counter uses JK flip-flops. If the propagation delay of each flip-flop is 50 ns, the maximum clock frequency is equal to—
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Given propagation delay of one F/F = 50 ns. To design modulo-16 ripple counter we need 4 F/Fs. So, total propagation delay = 50 × 4 = 200 ns. Therefore, the maximum operating frequency
fmax = 1 = 1 = 5 MHz n × tpd 200 ns Correct Option: D
Given propagation delay of one F/F = 50 ns. To design modulo-16 ripple counter we need 4 F/Fs. So, total propagation delay = 50 × 4 = 200 ns. Therefore, the maximum operating frequency
fmax = 1 = 1 = 5 MHz n × tpd 200 ns
- A ring counter consist of five flip-flops will have—
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A ring counter consist of five flip-flops will have 5 states.
Correct Option: A
A ring counter consist of five flip-flops will have 5 states.