Digital electronics miscellaneous
- The binary number 110011 is to be converted to Gray code. The number of gates and type required are—
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We know that for converting binary number into Gray code, we require XOR gate. For converting n bit binary number we require (n–1) XOR gate. So, in order to convert binary number 110011 (i.e., 6 bits) we require 6–1 = 5 XOR gates.
Correct Option: D
We know that for converting binary number into Gray code, we require XOR gate. For converting n bit binary number we require (n–1) XOR gate. So, in order to convert binary number 110011 (i.e., 6 bits) we require 6–1 = 5 XOR gates.
- For the figure given below—
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NA
Correct Option: B
NA
- If the input to the digital circuit shown below, consisting of a cascade of 20 EX-OR gates is X. Then the output Y is equal to— 1 X Y
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A = 1X + X1 = X
B = X X̿ + X X = X + X = 1
So, output after 20 Ex-OR gate is 1.
Correct Option: B
A = 1X + X1 = X
B = X X̿ + X X = X + X = 1
So, output after 20 Ex-OR gate is 1.
- The output of the logic gate in the given figure is—
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Given figure
Y = A 0+ A·0 = A
Correct Option: D
Given figure
Y = A 0+ A·0 = A
- Assume that only the X and Y logic inputs are available and their complements X and Y are not available. What is the minimum number of two input NAND gates required to implement X ⊕ Y?
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Let the function be F
F = X ⊕ Y = XY + YX
This require four NAND gates to implement. Implementation is shown below.
Correct Option: C
Let the function be F
F = X ⊕ Y = XY + YX
This require four NAND gates to implement. Implementation is shown below.
