Time and Work
- 10 men and 15 women finish a work in 6 days. One man alone finishes that work in 100 days. In how many days will one women can finish the work ?
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∵ One man alone finishes te work in 100 days.
⇒ 10 men can finish the work in 10 day.
⇒ 15 women can finish work in one days = 1/6 - 1/10 = 1/15 workCorrect Option: D
∵ One man alone finishes te work in 100 days.
⇒ 10 men can finish the work in 10 day.
⇒ 15 women can finish work in one days = 1/6 - 1/10 = 1/15 work
⇒ 15 women finish the whole work in 15 days
∴ 1 women finishes the whole work in = 15 x 15 = 225 days
- Two friend A and B working together completed a work in 26 days. Their skills of doing the work are in the ratio 8 : 5. How many days will B take, if engaged alone ?
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Skill ratio of A and B = 8 : 5
So, the time taken by A and B 5W and 8W, respectively.
According to the question, 1/8W + 1/5W = 1/26Correct Option: A
Skill ratio of A and B = 8 : 5
So, the time taken by A and B 5W and 8W, respectively.
According to the question, 1/8W + 1/5W = 1/26
∴ W = (13 x 26)/40
Now, time taken by B is 8W = 8 x 13 x 26/40
= 673/5 days.
- X can do 1/4 of work in 10 days, Y can do 40% of the same work in 40 days and Z can do 1/3 of the work in 13 days. Who will complete the work first ?
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Time taken to complete the work by X =10 x 4 = 40 = 40 days
Time taken to complete the work by Y = (40 x 100)/40 = 100 days
Time taken to complete the work by Z = 13 x 3 = 39 daysCorrect Option: C
Time taken to complete the work by X =10 x 4 = 40 = 40 days
Time taken to complete the work by Y = (40 x 100)/40 = 100 days
Time taken to complete the work by Z = 13 x 3 = 39 days
Hence, Z will complete the work first.
- When A alone does a piece of work, he takes 25 days more than the time taken by (A + B) to complete that particular work, while B alone takes 49 days more than the time taken by (A + B) to finish the same work . A and B together will take what time for finish this work?
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According to the formula,
Required time = √ab
Where a = 25 and b = 49
Correct Option: A
According to the formula,
Required time = √ab
Where a = 25 and b = 49
∴ Require time = √25 x 49 = 5 x 7
= 35 days
- If one man or two woman or three boys can finish a work in 88 days , then how many days will one man one woman and one boys together take to finish the same work ?
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1 man = 2 woman = 3 boys
∴ 1 man + 1 woman + 1 boy = (3 + 3/2 + 1) boys = 11/2 boys
Here M1 = 3 M2 = 11/2, D1 = 88 and D2 = ?
According to the formula
M1D1 = M2D2
∴ D2 = M1D1/M2Correct Option: C
1 man = 2 woman = 3 boys
∴ 1 man + 1 woman + 1 boy = (3 + 3/2 + 1) boys = 11/2 boys
Here M1 = 3 M2 = 11/2, D1 = 88 and D2 = ?
According to the formula
M1D1 = M2D2
∴ D2 = M1D1/M2
∴ Required number of days
= 3 x 2 x 88/11 = 3 x 2 x 8 = 48 days