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If one man or two woman or three boys can finish a work in 88 days , then how many days will one man one woman and one boys together take to finish the same work ?
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- 46 boys
- 54 days
- 48 days
- 44 days
Correct Option: C
1 man = 2 woman = 3 boys
∴ 1 man + 1 woman + 1 boy = (3 + 3/2 + 1) boys = 11/2 boys
Here M1 = 3 M2 = 11/2, D1 = 88 and D2 = ?
According to the formula
M1D1 = M2D2
∴ D2 = M1D1/M2
∴ Required number of days
= 3 x 2 x 88/11 = 3 x 2 x 8 = 48 days
