Time and Work


  1. 20 women can complete apiece of work in 7 day. If 8 more women are put on the job. In how many days will they complete the work?









  1. View Hint View Answer Discuss in Forum

    Given, M1 = 20 D1 = 7, M2 = 20 + 8 = 28
    and D2 = ?
    Using formula, M1D1 = M2D2

    Correct Option: B

    Given, M1 = 20 D1 = 7, M2 = 20 + 8 = 28
    and D2 = ?
    Using formula, M1D1 = M2D2
    ⇒ 20 x 7 = 28 x D2
    ∴ D2 = (20 x 7)/28 = 5 days


  1. 20 men can cut 30 tree in 4 h. If 4 men leave the job, how many trees will be cut in 12 h?









  1. View Hint View Answer Discuss in Forum

    Given, M1 = 20, T1 = 4, W1 = 30,
    M2 = 20 - 4 = 16, T2 = 12 and W2 = ?
    According to the formula,
    M1T1W2 = M2T2W1

    Correct Option: A

    Given, M1 = 20, T1 = 4, W1 = 30,
    M2 = 20 - 4 = 16, T2 = 12 and W2 = ?
    According to the formula,
    M1T1W2 = M2T2W1
    ⇒ 20 x 4 x W2 = 16 x 12 x 30
    ∴ W2 = (16 x 12 x 30)/(20 x 4) = 12 x 6 = 72 trees



  1. 12 men can do a piece of work in 24 days. How many days are needed to go complete the work, if 8 men do this work ?









  1. View Hint View Answer Discuss in Forum

    Given, M1 = 12, M2 = 8 , D1 = 24 , W1 = 1, W2 = 1
    According to the formula,
    M1D1W2 = M2D2W1

    Correct Option: B

    Given, M1 = 12, M2 = 8 , D1 = 24 , W1 = 1, W2 = 1
    According to the formula,
    M1D1W2 = M2D2W1
    ⇒ 12 x 24 x 1= 8 x D2 x 1
    ∴ D2 = (12 x 24)/8
    = 12 x 3 = 36 days


  1. 40 men can build a wall 200 m long in 12 days, working 8h a day. What will be the number of days that 30 men will take to built a similar wall 300 m long, working 6h per days.









  1. View Hint View Answer Discuss in Forum

    Given, M1 = 40, W1 = 200, T1 = 8, D1 = 12,
    M2 = 30, W2 = 300, T2 = 6 and D2 = ?
    Then, using formula
    M1T1D1W2 = M2T2D2W1

    Correct Option: A

    Given, M1 = 40, W1 = 200, T1 = 8, D1 = 12,
    M2 = 30, W2 = 300, T2 = 6 and D2 = ?
    Then, using formula
    M1T1D1W2 = M2T2D2W1
    ⇒ 40 x 8 x 12 x 300 = 30 x 6 x D2 x 200
    ∴ D2 = (40 x 8 x 12 x 300)/(30 x 6 x 200) = 32 days.



  1. A and B can do a piece of work in 60 days and 75 days, respectively. Both begin together but after a certain time A leaves off. In such case B finishes the remaining work in 30 days. After how many days did A leave ?









  1. View Hint View Answer Discuss in Forum

    Here A = 60 days, B = 75 days, D = 30, T = ?
    ∴ Required time = (B - D) x [A/(A + B)]

    Correct Option: C

    Here A = 60 days, B = 75 days, D = 30, T = ?
    ∴ Required time = (B - D) x [A/(A + B)]
    = (75 - 30) x [60/(60 + 75)]
    = (45 x 60)/135 = 20 days
    ∴ Required time = 20 days