LCM and HCF
- The number of prime factors in the expression (6)10 x (7)17 x (11)27 is ?
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Since 2, 3, 7, 11 are prime numbers and the given expression is
210 x 310 x 717 x 1127Correct Option: B
Since 2, 3, 7, 11 are prime numbers and the given expression is
210 x 310 x 717 x 1127
So the number of prime factors in the given expression is (10 + 10 + 17 + 27 ) = 64.
- What least number must be subtracted from 1294 so that the remainder when divided by 9, 11, 13 will leave in each case the same remainder 6 ?
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L. C .M of 9, 11, 13 is 1287
On dividing 1294 by 1287, the remainder is 7 .Correct Option: B
L. C .M of 9, 11, 13 is 1287
On dividing 1294 by 1287, the remainder is 7 .
∴ 1 must be subtracted from 1294, so that 1293 when divided by 9, 11, 13 leaves in each case the same remainder 6 .
- The least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder is ?
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L.C.M of 5, 6 , 7, 8 is 840
So, the number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2Correct Option: B
L.C.M of 5, 6 , 7, 8 is 840
So, the number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2
∴ Required number = (840 x 2 + 3 ) = 1683
- The greatest number by which if 1657 and 2037 are divided the remainders will be 6 and 5 respectively, is ?
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Required number = H.C.F of (1657 - 6) and (2037 - 5)
= H.C.F of 1651 and 2032Correct Option: A
Required number = H.C.F of (1657 - 6) and (2037 - 5)
= H.C.F of 1651 and 2032
= 127
- Six bell commence tolling together and toll at intervals of 5, 10, 15, 20, and 30 s, respectively. In 60 min, how many times do they toll together?
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LCM of 5, 10, 15, 20, 25 and 30 is 300. So, the bell will toll together after every 300s (5min).
Correct Option: C
LCM of 5, 10, 15, 20, 25 and 30 is 300. So, the bell will toll together after every 300s (5min).
So, the number of times they toll together = 60/5 + 1=13