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The least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder is ?
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- 1677
- 1683
- 2523
- 3363
Correct Option: B
L.C.M of 5, 6 , 7, 8 is 840
So, the number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2
∴ Required number = (840 x 2 + 3 ) = 1683
