51. The gate whose output is Low if and only if all the inputs are High is—

1. 1. NAND

   
   
   

   2. NOR

   
   
   

   3. OR

   
   
   

   4. AND

   
   
   

---

1. View Hint View Answer Discuss in Forum

   Truth Table of NAND Gate
   

   Correct Option: A

   Truth Table of NAND Gate
   

---

52. Hamming codes are used for error detection and correction. If the minimum hamming distance is m, then the number of errors correctable is—

1. 1. equal to m

   
   
   

   2. less than m/2

   
   
   

   3. equal to 2m

   
   
   

   4. greater than m

   
   
   

---

1. View Hint View Answer Discuss in Forum

   Hamming codes are used for error detection and correction. If the minimum Hamming distance is m, then the number of error correctable is less than m/2.

   Correct Option: B

   Hamming codes are used for error detection and correction. If the minimum Hamming distance is m, then the number of error correctable is less than m/2.

---

---

53. Hamming codes are used for error detection and correction. If the minimum hamming distance is m, then the number of errors correctable is—

1. 1. equal to m

   
   
   

   2. less than m/2

   
   
   

   3. equal to 2m

   
   
   

   4. greater than m

   
   
   

---

1. View Hint View Answer Discuss in Forum

   Hamming codes are used for error detection and correction. If the minimum Hamming distance is m, then the number of error correctable is less than m/2.

   Correct Option: B

   Hamming codes are used for error detection and correction. If the minimum Hamming distance is m, then the number of error correctable is less than m/2.

---

54. The number of bits in a binary PCM system is increased from n to n + 1. As a result, the signal to quantization noise ratio will improve by the—

1. 1. n + 1

      n

   
   
   

   2. 2^{(n + 1)/ n}

   
   
   

   3. 2^{2 (n + 1)/ n}

   
   
   

   4. which is independent of n

   
   
   

---

1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: C

   NA

---

---

55. By placing an inverter between both input of an S–R flipflop, it becomes—

1. 1. J–K flip-flop

   
   
   

   2. D flip-flop

   
   
   

   3. T flip-flop

   
   
   

   4. Master slave flip-flop

   
   
   

---

1. View Hint View Answer Discuss in Forum

   D flip-flop
   

   Correct Option: B

   D flip-flop
   

---